How do you simplify #(4-5i)(3+2i)#?

1 Answer
George C.
Jun 5, 2016

#22-7i#

Explanation:

Use the FOIL mnemonic if it helps you and #i^2=-1# to find:

#(4-5i)(3+2i) = overbrace((4*3))^"First" + overbrace((4*2i))^"Outside" + overbrace((-5i*3))^"Inside" + overbrace((-5i*2i))^"Last"#

#=12+8i-15i+10#

#=22-7i#

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