How do you simplify #4.98^0#?

2 Answers
Jan 20, 2017

Answer:

#4.98^0=color(green)1#

Explanation:

Any number (excluding perhaps zero) to the power of #0# is equal to #1#

Consider the following sequence for any number #n# which is not zero:

#color(white)("XXX")n^4 = nxxnxxnxxn#

#color(white)("XXX")n^3=(n^4)/n=nxxnxxn#

#color(white)("XXX")n^2 = (n^3)/n=nxxn#

#color(white)("XXX")n^1=(n^2)/n=n#

#color(white)("XXX")n^0 = (n^1)/n = n/n =1#

...and we could continue on:

#color(white)("XXX")n^(-1) = (n^0)/n =1/n#

#color(white)("XXX")n^(-2)=(n^(-1))/n=1/(n^2)#

#color(white)("XXX")n^(-3)=(n^(-2))/n=1/(n^3)#

...and so on...

Jan 20, 2017

Answer:

1

Explanation:

Another way of writing #4.98^0# is : #4.98/4.98 = 1#