How do you simplify #4/m^ -7#?

1 Answer
Mar 27, 2016

Answer:

#4/m^(-7) = 4m^7# with exclusion #m != 0#

Explanation:

If #m != 0# then:

#m^(-7) = 1/underbrace(m xx m xx .. xx m)_"7 times" = 1/m^7#

So:

#4/m^(-7)=4/(1/m^7) = 4 m^7#

Note that if #m = 0# then the left hand side is undefined, but the right hand side is defined, so #m=0# is an excluded value.