How do you simplify #4/m^ -7#?
1 Answer
Mar 27, 2016
#4/m^(-7) = 4m^7# with exclusion#m != 0#
Explanation:
If
#m^(-7) = 1/underbrace(m xx m xx .. xx m)_"7 times" = 1/m^7#
So:
#4/m^(-7)=4/(1/m^7) = 4 m^7#
Note that if