How do you simplify #(4r^{2}-3r+2)-(-r^{2}-3r)#?

1 Answer
Apr 4, 2018

#5r^2 + 2#

Explanation:

#(4r^2-3r+2)-(-r^2-3r)#

The first thing we need to do is distribute the #-# to everything in its parenthesis:
#4r^2-3r+2+r^2+3r#

And now we just combine like terms and simplify:
#4r^2 + r^2 = 5r^2#

#-3r + 3r = 0#

So the simplified answer is:
#5r^2 + 2#

Hope this helps!