First, subtract #color(red)(4x)# and add #color(blue)(8)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#4x - color(red)(4x) + 2 + color(blue)(8) = 6x - color(red)(4x) - 8 + color(blue)(8)#

#0 + 10 = (6 - color(red)(4))x - 0#

#10 = 2x#

Now, divide each side of the fraction by #color(red)(2)# to solve for #x# while keeping the equation balanced:

#10/color(red)(2) = (2x)/color(red)(2)#

#5 = (color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2))#

#5 = x#

#x = 5#