How do you simplify #(4x+7)(3x+2)#?

1 Answer
Feb 15, 2017

Answer:

See the entire simplification process below:

Explanation:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(4x) + color(red)(7))(color(blue)(3x) + color(blue)(2))# becomes:

#(color(red)(4x) xx color(blue)(3x)) + (color(red)(4x) xx color(blue)(2)) + (color(red)(7) xx color(blue)(3x)) + (color(red)(7) xx color(blue)(2))#

#12x^2 + 8x + 21x + 14#

We can now combine like terms:

#12x^2 + (8 + 21)x + 14#

#12x^2 + 29x + 14#