How do you simplify #(4x+7)(3x+2)#?

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Answer 1 · 2017-02-15T13:18:39

See the entire simplification process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(4x) + color(red)(7))(color(blue)(3x) + color(blue)(2))# becomes:

#(color(red)(4x) xx color(blue)(3x)) + (color(red)(4x) xx color(blue)(2)) + (color(red)(7) xx color(blue)(3x)) + (color(red)(7) xx color(blue)(2))#

#12x^2 + 8x + 21x + 14#

We can now combine like terms:

#12x^2 + (8 + 21)x + 14#

#12x^2 + 29x + 14#