How do you simplify #5!#?

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Answer 1 · 2018-04-25T01:59:16

#5 ! =120#

In general,

#n ! =(n)(n-1)(n-2)*...*(3)(2)(1)#

That is, when given a factorial, to determine its value, we simply multiply by every integer below it until we get to #1.#

So,

#5 ! =5*4*3*2*1#

#=20*3*2*1#

#=60*2*1#

#=120*1=120#