How do you simplify #5 sqrt40#? Algebra Radicals and Geometry Connections Simplification of Radical Expressions 1 Answer Marie Mar 6, 2017 Answer: #10sqrt(10)# Explanation: Starting with #sqrt(40)# #sqrt(4*10)# #sqrt(2^2*10)# #2sqrt(10)# Now, to include the #5# you have to multiply #2sqrt(10)# by #5# which equals #10sqrt(10)# Related questions How do you simplify radical expressions? How do you simplify radical expressions with fractions? How do you simplify radical expressions with variables? What are radical expressions? How do you simplify #root{3}{-125}#? How do you write # ""^4sqrt(zw)# as a rational exponent? How do you simplify # ""^5sqrt(96)# How do you write # ""^9sqrt(y^3)# as a rational exponent? How do you simplify #sqrt(75a^12b^3c^5)#? How do you simplify #sqrt(50)-sqrt(2)#? See all questions in Simplification of Radical Expressions Impact of this question 244 views around the world You can reuse this answer Creative Commons License