How do you simplify #(5y-10)/-5#?

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Answer 1 · 2015-05-12T23:35:03

Write it as:
#5y/-5-10/-5=cancel(5)y/-cancel(5)-cancel(10)^2/-cancel(5)=-y+2#

Hope it helps!

Answer 2 · 2015-05-12T23:54:38

The answer is #-y+2# .

A different approach from the previous answer:

Simplify #(5y-10)/-5# .

Factor out the #5# in the numerator.

#(5y-10)/-5# =

#(5(y-2))/-5#

Divide the #5# by the #-5#.

#(cancel5(y-2))/cancel(-5)=-1(y-2)# =

#-y+2#