How do you simplify #6÷2(1+2)# using order of operations?
Using PEDMAS ie 'order of operations '
Parenthesis ( brackets ) must be done first followed by multiplication then division . Division and Multiplication are of equal precedence.
# rArr 6 ÷ 2 ( 1 + 2 )#
#6 ÷ 2 xx 3#
and evaluating from ' left to right' to obtain answer.
There is only one term, but the bracket needs to be calculated first.
Division and multiplication are equally strong, it does not matter which is done first, as long as the division is by 2 and the multiplication is by 3
By the associative law we have:
This is NOT equal to