# How do you simplify (6-5i)(4-i)?

Sep 5, 2016

$19 - 26 i$

#### Explanation:

distribute the brackets using, for example, the FOIL method.

$\Rightarrow \left(6 - 5 i\right) \left(4 - i\right) = 24 - 6 i - 20 i + 5 {i}^{2}$

$\textcolor{\mathmr{and} a n \ge}{\text{Reminder }} \textcolor{red}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} \textcolor{b l a c k}{{i}^{2} = {\left(\sqrt{- 1}\right)}^{2} = - 1} \textcolor{w h i t e}{\frac{a}{a}} |}}}$

$\Rightarrow 24 - 26 i - 5 = 19 - 26 i$

Thus $\left(6 - 5 i\right) \left(4 - i\right) = 19 - 26 i$