# How do you simplify (6i)(-2i)?

Oct 21, 2016

$12$

#### Explanation:

We can rearrange this multiplication problem:

$\left(6 i\right) \left(- 2 i\right) = \left(6 \cdot - 2\right) \left(i \cdot i\right) = - 12 {i}^{2}$

Recall the definition of $i$, that it $i = \sqrt{- 1}$. Squaring both sides shows that ${i}^{2} = - 1$. Thus

$- 12 {i}^{2} = - 12 \left(- 1\right) = 12$