How do you simplify #-6i^3+i^2#? Precalculus Complex Numbers in Trigonometric Form Powers of Complex Numbers 1 Answer Konstantinos Michailidis Sep 19, 2016 #6*i-1# Explanation: We know that #i^2=-1# #i^3=i^2*i=-i# Hence #-6*i^3+i^2=-6*(-i)-1=6*i-1# Answer link Related questions How do I use DeMoivre's theorem to find #(1+i)^5#? How do I use DeMoivre's theorem to find #(1-i)^10#? How do I use DeMoivre's theorem to find #(2+2i)^6#? What is #i^2#? What is #i^3#? What is #i^4#? How do I find the value of a given power of #i#? How do I find the #n#th power of a complex number? How do I find the negative power of a complex number? Write the complex number #i^17# in standard form? See all questions in Powers of Complex Numbers Impact of this question 1698 views around the world You can reuse this answer Creative Commons License