How do you simplify #(6x + 2)(2x^2 - 6x + 1)#?

1 Answer
Feb 20, 2017

Answer:

See the entire simplification process below:

Explanation:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(6x) + color(red)(2))(color(blue)(2x^2) - color(blue)(6x) + color(blue)(3))# becomes:

#(color(red)(6x) xx color(blue)(2x^2)) - (color(red)(6x) xx color(blue)(6x)) + (color(red)(6x) xx color(blue)(1)) + (color(red)(2) xx color(blue)(2x^2)) - (color(red)(2) xx color(blue)(6x)) + (color(red)(2) xx color(blue)(1))#

#12x^3 - 36x^2 + 6x + 4x^2 - 12x + 2#

We can now group and combine like terms:

#12x^3 - 36x^2 + 4x^2 + 6x - 12x + 2#

#12x^3 + (-36 + 4)x^2 + (6 - 12)x + 2#

#12x^3 - 32x^2 - 6x + 2#