# How do you simplify (- 7) ^ { 4} \cdot ( - 3) ^ { 4} ?

Sep 21, 2017

${\left(- 7\right)}^{4} \cdot {\left(- 3\right)}^{4}$

#### Explanation:

It can't be simplified any more, except if you want to Evaluate the answer..

${\left(- 7\right)}^{4} \cdot {\left(- 3\right)}^{4}$ is in it's simplest term, where it can't be simplified any longer.

But if they would have been same base of numbers (same set of digits), they it can be simplified as only one value..

For example, if we would have $- {3}^{a} \cdot - {3}^{a}$ then it would have been simplified as ${9}^{a + a}$ where $a$ represent any integer..

Sep 22, 2017

$194481$

#### Explanation:

${\left(- 7\right)}^{4} = \left(- 7\right) \times \left(- 7\right) \times \left(- 7\right) \times \left(- 7\right)$

$\textcolor{w h i t e}{{\left(- 7\right)}^{4}} = 49 \times 49 = 2401$

${\left(- 3\right)}^{4} = \left(- 3\right) \times \left(- 3\right) \times \left(- 3\right) \times \left(- 3\right)$

$\textcolor{w h i t e}{{\left(- 3\right)}^{4}} = 9 \times 9 = 81$

$\Rightarrow {\left(- 7\right)}^{4} . {\left(- 3\right)}^{4}$

$= 2401 \times 81$

$= 194481$