How do you simplify #(-7i)(4i)(3-6i)#?

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Answer 1 · 2018-05-07T16:22:35

#84-168i#

multiply all the terms together.

you can start by multiplying #-7i# by#4i#:

#-7 * 4 = -28#

#i * i = i^2 = -1#

#=7i * 4i = -28 * -1#

#= 28#

#(-7i)(4i)(3-6i) = 28(3 - 6i)#

#28 * 3 = 84#

#28 * -6i = -168i#

#28(3-6i) = 84-168i#

hence, #(-7i)(4i)(3-6i) = 84-168i#

#84-168i# would be the expression in rectangular form.