How do you simplify #7root4(4a^3 b) * 3 sqrt(2a^2 b)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Sonnhard Jun 22, 2018 #42a^(7/4)*b^(3/4)# Explanation: We get #21*4^(1/4)*a^(3/4)*b^(1/4)*2^(1/2)*(a^2)^(1/2)*b^(1/2)# this #21*2^(1/2)*2^(1/2)*a^(3/4)*a*b^(1/4)*b^(1/2)# simplifying #21*2*a^(7/4)*b^(3/4)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1337 views around the world You can reuse this answer Creative Commons License