How do you simplify #7sqrt108#?

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Answer 1 · 2015-10-17T11:40:11

#42sqrt3#

get the #sqrt108#

= #sqrt((9)(4)(3)#

#9# and #4# are perfect square

= #(3)(2)sqrt3#

= #6sqrt3#

then multiply #7#

= #(7)(6)sqrt3#

= #42sqrt3#