How do you simplify #7sqrt108#?

Question

1566 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-10-17T11:40:11

#42sqrt3#

get the #sqrt108#

= #sqrt((9)(4)(3)#

#9# and #4# are perfect square

= #(3)(2)sqrt3#

= #6sqrt3#

then multiply #7#

= #(7)(6)sqrt3#

= #42sqrt3#