How do you simplify #(7t - 8) - ( - 7t - 8)#?

1 Answer

#14t#

Explanation:

We have two kinds of terms: ones that have a variable, #t#, and those that don't. We handle them separately.

Let's first distribute the negative sign on the right side:

#(7t-8)-(-7t-8)#

#7t-8+7t+8#

With the Communative Law, we can rearrange addition and subtraction, so let's group the #t# terms together and the non #t# terms together:

#7t+7t-8+8#

And the Associative Law says I can group different groups together and not change the value of the expression:

#(7t+7t)+(-8+8)#

In the first bracket, we have #7t# and 7 more #t#, for a total of #14t#. In the second bracket, we have a negative 8 and a positive 8, which add to 0. That all gives us:

#14t+0=14t#