How do you simplify #(-8)^(-1/3)#?

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Answer 1 · 2018-05-03T09:59:08

#-1/2#

#a^-n=1/a^n " "#[this is a proved result]

So,

#-8^(-1/3)=(-1/8)^(1/3)#

#(-1/8)^(1/3)= root(3)(-1/8)=-1/2#

Answer 2 · 2018-05-03T10:01:39

#(-8)^(-1/3)=-1/2#

#(-8)^(-1/3)=^"-3"sqrt(-8)#
#=1/(^"3"sqrt(-8))#
#=-1/2#
\0/ here's our answer !