# How do you simplify (81^(-3/2))^(-1/2)?

Sep 25, 2015

27

#### Explanation:

Since ${\left({A}^{p}\right)}^{q}$ = ${A}^{p \cdot q}$

(81^(−3/2))^(−1/2) = ${81}^{\frac{3}{4}}$

= ${\left(3 \cdot 3 \cdot 3 \cdot 3\right)}^{\frac{3}{4}}$

= ${3}^{3}$ = 27