How do you simplify #8sqrt27#?

1 Answer
EZ as pi
Jul 13, 2016

=#24sqrt3#

Explanation:

27 is not a perfect square and therefore does not have an exact square root.

Express 27 as the product of its prime factors.

#8sqrt27 = 8sqrt(3xx3xx3)" group factors in pairs"#

=#8sqrt(3^2xx3) " find root where possible"#

=# 8 xx 3 sqrt3#

=#24sqrt3#

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