# How do you simplify 8x^2-8- [3(x^2-1) +7]?

Jun 8, 2018

5${x}^{2}$-12

#### Explanation:

We will start by expanding the inner brackets.

8${x}^{2}$-8-[3(${x}^{2}$-1)+7]

So it becomes this by multiplying 3 with ${x}^{2}$ and $- 1$

8${x}^{2}$-8-[3${x}^{2}$-3+7]

Then we further simplify the insides of the brackets so it becomes,

8${x}^{2}$-8-[3${x}^{2}$+4]

Then we multiply $- 1$ with the insides of the bracket, so we get:

8${x}^{2}$-8-3${x}^{2}$-4

Then we bring and simplify like terms together:

8${x}^{2}$-3${x}^{2}$-8-4

This becomes:

5${x}^{2}$-12