How do you simplify #(8x^3-12x^2+6x-9)/(16x^4-9)#? Algebra Rational Equations and Functions Division of Polynomials 1 Answer Binayaka C. May 30, 2017 #(2x-3)/ (4x^2-3)# Explanation: # (8x^3 -12x^2 +6x -9) /(16 x^4 -9)# # = (8x^3 +6x -12x^2 -9) /((4x^2)^2 -3^2) # # = (2x(4x^2+3) - 3(4x^2+3))/((4x^2+3)(4x^2-3) # #=(cancel((4x^2+3)) (2x- 3))/(cancel((4x^2+3))(4x^2-3)# #(2x-3)/ (4x^2-3)# [Ans] Answer link Related questions What is an example of long division of polynomials? How do you do long division of polynomials with remainders? How do you divide #9x^2-16# by #3x+4#? How do you divide #\frac{x^2+2x-5}{x}#? How do you divide #\frac{x^2+3x+6}{x+1}#? How do you divide #\frac{x^4-2x}{8x+24}#? How do you divide: #(4x^2-10x-24)# divide by (2x+3)? How do you divide: #5a^2+6a-9# into #25a^4#? How do you simplify #(3m^22 + 27 mn - 12)/(3m)#? How do you simplify #(25-a^2) / (a^2 +a -30)#? See all questions in Division of Polynomials Impact of this question 1640 views around the world You can reuse this answer Creative Commons License