How do you simplify #(9n^4)^(1/2)#?

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Answer 1 · 2017-04-10T06:35:34

#3n^2#

We can distribute the fractional exponent through the expression:

#(9n^4)^(1/2)=9^(1/2)xx(n^4)^(1/2)#

I'm going to rewrite #9=3^2#

#(3^2)^(1/2)xx(n^4)^(1/2)#

We can now use the rule that #(x^a)^b=x^(ab)#

#3^(2xx(1/2))xxn^(4xx(1/2))#

#3^1xxn^2=3n^2#