How do you simplify #(-9w-3)/(3w+12)#? Algebra Rational Equations and Functions Division of Polynomials 1 Answer smendyka May 27, 2017 See a solution process below: Explanation: Factor a #color(red)(3)# from both the numerator and denominator and cancel the common term: #(-9w - 3)/(3w + 12) => (color(red)(3)(-3w - 1))/(color(red)(3)(w + 4)) =># #(cancel(color(red)(3))(-3w - 1))/(cancel(color(red)(3))(w + 4)) =># #(-3w - 1)/(w + 4)# Answer link Related questions What is an example of long division of polynomials? How do you do long division of polynomials with remainders? How do you divide #9x^2-16# by #3x+4#? How do you divide #\frac{x^2+2x-5}{x}#? How do you divide #\frac{x^2+3x+6}{x+1}#? How do you divide #\frac{x^4-2x}{8x+24}#? How do you divide: #(4x^2-10x-24)# divide by (2x+3)? How do you divide: #5a^2+6a-9# into #25a^4#? How do you simplify #(3m^22 + 27 mn - 12)/(3m)#? How do you simplify #(25-a^2) / (a^2 +a -30)#? See all questions in Division of Polynomials Impact of this question 1297 views around the world You can reuse this answer Creative Commons License