Question

How do you simplify and divide `(g^2+8g+15)(g+3)^-1`?

Answer 1

`(g^2 + 8g+15)/(g+3)=??`

Factorize the numerator..........

Explanation:

And thus, `g^2+8g+15=(g+5)(g+3)`

And thus, `(g^2 + 8g+15)/(g+3)=[(g+5)(g+3)]/(g+3)=[(g+5)cancel((g+3))]/cancel((g+3))`

`=` `g+5`

How did I know how to factorize `(g^2 + 8g+15)`? Given the question, I knew that `(g+3)` was likely to be a factor, and I proceeded from that basis.