# How do you simplify and find the restrictions for (6)/(x+3)?

Apr 25, 2017

See explanation

#### Explanation:

The function $\frac{6}{x + 3}$ will have a restricted domain at $x = - 3$.

We know this because the denominator of our function cannot be $0$ and to find what value this occurs, we set the denominator equal to $0$ such that:

$x + 3 = 0 \to x = - 3$

What this tells us that the graph will have a vertical asymptote at $x = - 3$

Thus our domain for this function is: $\left\{x | x \ne - 3\right\} \mathmr{and} \left(- \infty , - 3\right) \cup \left(- 3 , \infty\right)$