# How do you simplify (b^10/b^3)^-2?

May 7, 2016

#### Answer:

Apply the laws of Indices. See working below.

#### Explanation:

${\left({b}^{10} / {b}^{3}\right)}^{-} 2$ = $\left({b}^{-} \frac{20}{b} ^ - 6\right)$ = $\left({b}^{-} 20\right) \left({b}^{6}\right)$ = ${b}^{- 14}$