How do you simplify #(( ( c ^ { 4} y ^ { 2} ) ( a ^ { 1} c ^ { 5} x ^ { 3} ) ) ^ { 4} ) ( a ^ { 2} y ^ { 3} ) ( a ^ { 4} y ^ { 5} )#?

1 Answer

#a^10c^36x^12y^16#

Explanation:

#(((c^4y^2)(a^1c^5x^3))^4)(a^2y^3)(a^4y^5)#

Let's first note that there is a multiplication within a bracket that needs to be done before applying the 4th power:

#(color(red)(((c^4y^2)(a^1c^5x^3)))^4)(a^2y^3)(a^4y^5)#

For all multiplication where we have #x^axxx^b#, we can use the rule that #x^axxx^b=x^(a+b)#

#(color(red)(((a^1c^9x^3y^2)))^4)(a^2y^3)(a^4y^5)#

Now we can apply the 4th power. We can use the rule #(x^a)^b=x^(ab)#

#(color(red)(a^4c^36x^12y^8))(a^2y^3)(a^4y^5)#

For this last piece of the puzzle, we can use the first rule again:

#a^10c^36x^12y^16#