How do you simplify e^(1 + ln x)?

Mar 3, 2016

$e \cdot x$

Explanation:

Use the rule to split up the exponent:

${a}^{b + c} = {a}^{b} \left({a}^{c}\right)$

Thus:

${e}^{1 + \ln x} = {e}^{1} \left({e}^{\ln} x\right)$

Here:

${e}^{1} = e$

${e}^{\ln} x = x$

So:

${e}^{1 + \ln x} = e \cdot x$