Question

How do you simplify `( \frac { 3a ^ { 2} b c ^ { 4} } { 4a b ^ { 2} } ) ^ { 3}`?

Answer 1

See below

Explanation:

`((3a^cancel2cancelbc^4)/(4cancelab^cancel2))^3=(3^3a^3c^12)/(4^3b^3)=(27a^3c^12)/(64b^3)`