How do you simplify #\frac { 8b c ^ { 4} d ^ { 2} } { 8b ^ { 2} c ^ { 3} d ^ { 9} }#?

1 Answer
NJ
Mar 25, 2018

#=>(c)/(bd^7)#

Explanation:

#=>\frac { 8b c ^ { 4} d ^ { 2} } { 8b ^ { 2} c ^ { 3} d ^ { 9} }#

First, we can divide out the #8#s.

#=>(bc^4d^2)/(b^2c^3d^9)#

Next, let's simplify the #b# terms. The difference of powers between numerator and denominator is #1-2 = -1#. So we can write #b^1 = b# in the denominator.

#=>(c^4d^2)/(bc^3d^9)#

For #c# terms, the difference in powers is #4-3 = 1#. So we can write #c^1=c# in the numerator.

#=>(cd^2)/(bd^9)#

Last, the #d# terms. The difference in powers is #2-9 = -7#. So we can write #d^7# in the denominator.

#=>(c)/(bd^7)#

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