How do you simplify #\frac { a x } { b } + \frac { c x } { d } = e#?

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Answer 1 · 2018-03-09T03:05:27

#x=(bde)/(ad+cb)#

Multiply by #b# and #d#, then factor out #x#, and divide so that #x# is by itself:

#(ax)/b+(cx)/d=e#

#ax+(cxb)/d=eb#

#axd+cxb=ebd#

#x(ad+cb)=ebd#

#(xcolor(red)cancelcolor(black)((ad+cb)))/color(red)cancelcolor(blue)(ad+cb)=(ebd)/color(blue)(ad+cb)#

#x=(bde)/(ad+cb)#