How do you simplify #i(1+i) #?
1 Answer
Feb 10, 2016
i - 1 = - 1 + i
Explanation:
first step : distribute the bracket
hence i(1 + i ) =
# i + i^2 # now
# i^2 = (sqrt-1)^2 = -1 # and so i(1 + i ) = i - 1 = -1 + i