How do you simplify (-i)^3?

Nov 12, 2016

$i$

Explanation:

${\left(- i\right)}^{3}$ =$\left(- i\right)$ x $\left(- i\right)$ x $\left(- i\right)$

But $\left(- i\right)$ x $\left(- i\right)$ =$+ {i}^{2}$ = -1

So ${\left(- i\right)}^{3}$ =$\left(- i\right)$ x $\left(- i\right)$ x $\left(- i\right)$= $- i$ x -1= $i$

Nov 12, 2016

$i$

Explanation:

$i$ is $\sqrt{- 1}$.

Therefore, ${i}^{2}$ would be $- 1$...

$- {i}^{3} = - i \setminus \times \left(- i\right) \setminus \times \left(- i\right) = - 1 \setminus \times \left(- i\right) = i$