# How do you simplify i(3+i) and write the complex number in standard form?

##### 1 Answer
Aug 10, 2016

$- 1 + 3 i$

#### Explanation:

First step is to distribute the bracket.

$\Rightarrow i \left(3 + i\right) = 3 i + {i}^{2}$

$\textcolor{\mathmr{and} a n \ge}{\text{Reminder }} \textcolor{red}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} \textcolor{b l a c k}{{i}^{2} = {\left(\sqrt{- 1}\right)}^{2} = - 1} \textcolor{w h i t e}{\frac{a}{a}} |}}}$

$\Rightarrow i \left(3 + i\right) = 3 i + {i}^{2} = - 1 + 3 i \text{ in standard form}$