How do you simplify #Log(x+4)=2log(x-2)#?

1 Answer
Dec 25, 2015

#x=5#

Explanation:

Simplify the right hand side using the logarithm rule:

#color(white)(sss)alog_b(c)=log_b(a^c)#

#log(x+4)=log((x-2)^2)#

Exponentiate both sides, which undoes both logarithms, leaving us with:

#x+4=(x-2)^2#

Distribute and simplify.

#x+4=x^2-4x+4#

#0=x^2-5x#

#0=x(x-5)#

#x=0,5#

However, the answer #x=0# is thrown out, since plugging in #0# in #2log(x-2)# would result in having to find the logarithm of a negative number, which is impossible.

Thus, the only valid answer is

#x=5#

graph{log(x+4)-2log(x-2) [-8.24, 17.07, -3.01, 9.65]}