How do you simplify #log(x(x^3+9)^-1/2)#?

1 Answer
Jul 22, 2017

#log(x)-log(x^3+9)-log(2)#

Explanation:

For multiplying the source values you add the logs
For dividing the source values you subtract the logs
For indices you multiply the log of the source value by the indices.

Set as #log(axxb^(-1)-:c)#

This gives:

#log(a)+[color(white)(2/2)(-1)xxlog(b)" "]-log(c)#

This gives:

#log(x)-log(x^3+9)-log(2)#