# How do you simplify (m^7n^4p)/(m^3n^3p)?

${m}^{4} n$ (if $m , n , p ,$ are all non-zero)
We know that ${a}^{m} / {a}^{n} = {a}^{m - n}$, for $a \ne 0$.
So, provided $m , n , p ,$ are all non-zero, the result is:
${m}^{7} / {m}^{3} {n}^{4} / {n}^{3} \frac{p}{p} = {m}^{4} n$