How do you simplify #((n+1)!) /( (n-1)!)#?

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#n^2+n#

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Write #((n+1)!)/((n-1)!) # as #((n+1)(n)(n-1)!)/((n-1)!) #

#((n+1)(n)cancel((n-1))!)/cancel((n-1)!) #

#= (n+1)n=n^2+n#

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