Question

How do you simplify ((n+1)!(n-1)!) / (n!)^2 ?

Answer 1

The answer is `1 + 1/n`

Explanation:

We have:

`((n + 1)!(n - 1)!)/((n!)(n!)`

`((n + 1)n!(n - 1)!)/(n!(n)(n - 1)!)`

`(n +1)/n`

`1+ 1/n`

Hopefully this helps!