How do you simplify #((n+3)!)/(n!)#?

1 Answer
Tony B
Nov 11, 2015

#n^3+6n^2 +11n +6#

Explanation:

#((n+3)(n+2)(n+1)n!)/(n!)#

#(n+3)(n+2)(n+1) times (n!)/(n!)#

#(n+3)(n+2)(n+1)#

#(n+3)(n^2+3n+2)#

#n^3+3n^2+2n +3n^2+9n+6#

#n^3+6n^2 +11n +6#

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