Question

How do you simplify `(p^2-64)/(p+8)`?

Answer 1

`p-8`

Explanation:

Notice that `8xx8=64`

Write as

`" "(p^2-8^2)/(p+8)`

But `p^2-8^2 = (p+8)(p-8)`

`(cancel((p+8))(p-8))/(cancel(p+8))`

`p-8`