How do you simplify #root3(-150,000)#?

1 Answer
Apr 19, 2016

Answer:

#=-10root3(150)#

Explanation:

First, you'll need to know this fact:, #rootn(ab)=rootn(a)*rootn(b)#, basically saying that you can split the big root sign into two (or even more) smaller ones.

Applying that to the question:
#root3(-150000)=root3(150)*root3(-1)*root3(1000)#

#=root3(150)*-1*10#
#=-10root3(150)#