How do you simplify #root3 2/root3 6#?

1 Answer
Mar 17, 2016

Answer:

#root3(2)/root3(6)=root3(3^2)/3=root3(9)/3#

Explanation:

#root3(2)/root3(6)=root3(cancel(2)^color(magenta)1/cancel(6)^color(magenta)3)=root3(1/3)=1/root3(3)#

Now the radical is in a form that could be rationalized

#1/root3(3)=1/root3(3)*root3(3^2)/root3(3^2)=root3(3^2)/3#