# How do you simplify root4(16)?

Jul 9, 2018

$\sqrt[4]{16} = 2$

#### Explanation:

Write the radicand as the product of its prime factors.

$\sqrt[4]{16} = \sqrt[4]{{2}^{4}}$

In this case, the expression simplifies very nicely.

$\sqrt[4]{16} = 2$

Jul 9, 2018

$. \sqrt[4]{16} = 2$

#### Explanation:

$\sqrt[4]{16}$

$\therefore = \sqrt[4]{2 \cdot 2 \cdot 2 \cdot 2}$

$\therefore = \sqrt{2} \cdot \sqrt{2} \cdot \sqrt{2} \cdot \sqrt{2} = 2$

$\sqrt{a} \cdot \sqrt{a} \cdot \sqrt{a} \cdot \sqrt{a} = a$

$\therefore \sqrt[4]{16} = 2$

Jul 9, 2018

$2$

#### Explanation:

We can rewrite $16$ as ${2}^{4}$, which allows us to now have the expression:

$\sqrt[4]{{2}^{4}}$

The Root $4$ and exponent $4$ cancel, and we're left with

$2$

Hope this helps!