How do you simplify #root4(16)#?

3 Answers
Jul 9, 2018

Answer:

#root(4)16 = 2#

Explanation:

Write the radicand as the product of its prime factors.

#root(4)16 = root(4)(2^4)#

In this case, the expression simplifies very nicely.

#root(4)16 = 2#

Jul 9, 2018

Answer:

#.root4(16)=2#

Explanation:

#root4(16)#

#:.=root4(2*2*2*2)#

#:.=sqrt 2*sqrt2*sqrt2*sqrt2=2#

#sqrt a*sqrta*sqrta*sqrta=a#

#:.root4(16)=2#

Jul 9, 2018

Answer:

#2#

Explanation:

We can rewrite #16# as #2^4#, which allows us to now have the expression:

#root4(2^4)#

The Root #4# and exponent #4# cancel, and we're left with

#2#

Hope this helps!