# How do you simplify root4(80)?

Jun 16, 2016

$= 2 \sqrt{5}$

#### Explanation:

It helps to write a number as the product of its prime factors first.
$80 = 2 \times 2 \times 2 \times 2 \times 5$

$80 = {2}^{4} \times 5$

At least we can find the 4th root of part of it and then leave the rest as a radical.

$\sqrt[4]{80} = \sqrt[4]{{2}^{4} \times 5}$

$= 2 \sqrt{5}$