How do you simplify #sin(pi/2-x)tanx#?
1 Answer
Jul 23, 2016
Explanation:
Using the
#color(blue)"trig. identities"#
#color(orange)"Reminder"#
#color(red)(|bar(ul(color(white)(a/a)color(black)(sin(pi/2-x)=cosx)color(white)(a/a)|)))# and
#color(red)(|bar(ul(color(white)(a/a)color(black)(tanx=sinx/(cosx))color(white)(a/a)|)))#
#rArrsin(pi/2-x)tanx=cancel(cosx)xxsinx/(cancel(cosx))=sinx#