How do you simplify #sqrt(432)#?
2 Answers
Aug 20, 2016
Explanation:
#432 = 2^4*3^3 = 2*2*3*2*2*3*3 = 12^2*3#
So we find:
#sqrt(432) = sqrt(12^2*3) = sqrt(12^2)*sqrt(3) = 12sqrt(3)#
Aug 20, 2016
Explanation:
Let us factorize given the number
we observe that
paring and taking one digit for each pair out of the square root sign we get